Radians, Arcs and Sectors (AI HL)

At HL, angles at the centre of a circle are measured in radians rather than degrees, and that single change simplifies both the arc-length and sector-area formulas. This page covers the two radian formulas, where they come from, and the mistakes that cost marks when students default back to the degree versions from SL. It's part of the broader Geometry & Trigonometry topic.

14 questions on this sub-topic.

Practise radians, arcs and sectors → Try exam-style questions

The two formulas

Covered under IB syllabus reference AHL3.7: the definition of a radian, and using radians to find arc length and sector area. Both formulas are in the formula booklet, but only work correctly when the angle is in radians.

Arc length

\(s = r\theta\)

\(\theta\) must be in radians. Use this when the question gives (or asks for) the length of the curved edge of a sector.

Sector area

\(A = \dfrac{1}{2}r^2\theta\)

Also needs \(\theta\) in radians. This replaces the degree-based \(\tfrac{\theta}{360}\times\pi r^2\) formula you may have seen at SL.

Want the full topic overview, syllabus table and GDC guidance? See Geometry & Trigonometry (including using your GDC).

Worked examples

1
Easy
No calc
[2 marks]

A circle has radius 9 cm.

Find the length of an arc subtending an angle of \(\tfrac{2\pi}{3}\) rad at the centre.

Worked solution

Arc length \(s=r\theta\), with \(\theta\) in radians (it is). M1
\(s=9\times\tfrac{2\pi}{3}=6\pi\approx 18.8\text{ cm}.\) A1

M1 For using the arc length formula \(s=r\theta\) A1 \(s=6\pi\)
2
Medium
Calculator
[4 marks]

A sector has radius 10 cm and angle \(1.2\) radians.

Find the arc length and sector area.

Worked solution

Arc \(= r\theta = 10(1.2)\) M1 \(= 12\) cm. A1
Area \(= \tfrac12 r^2\theta\) M1 \(= \tfrac12(100)(1.2) = 60\) cm². A1

M1 \(s=r\theta\) A1 Correct answer of \(12\) M1 \(\tfrac12 r^2\theta\) A1 Correct answer of \(60\)

Common mistakes

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Quick answers

What is the formula for the length of an arc in radians?

\(s = r\theta\), where \(r\) is the radius and \(\theta\) is the angle subtended at the centre, measured in radians.

What is the formula for the area of a sector in radians?

\(A = \tfrac12 r^2\theta\), with \(\theta\) in radians - not the degree version \(\tfrac{\theta}{360}\times\pi r^2\) you may have used at SL.

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