3D Geometry (AI HL)

Three-dimensional problems look intimidating but almost always reduce to something familiar: a distance formula with an extra coordinate, a standard solid's volume or surface area, or a right-angled triangle hiding inside a box, cone or pyramid. This page covers the skills specific to solids and space, with worked examples and the traps that catch students under exam pressure. It's part of the broader Geometry & Trigonometry topic.

11 questions on this sub-topic.

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The key tools

Covered under IB syllabus reference SL3.1: the distance between two points in 3D and their midpoint, volume and surface area of standard solids, and the angle between two lines or between a line and a plane.

3D distance

\(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\)

The 2D distance formula with a third coordinate added. The midpoint formula extends the same way, averaging each coordinate.

Volume and surface area

Cones, spheres, hemispheres, pyramids and combinations of these are all on the formula booklet - non-standard solids like a frustum have their formula given in the question.

✓ Standard solids in the formula booklet

Want the full topic overview and syllabus table, plus GDC guidance for these calculations? See Geometry & Trigonometry (including using your GDC).

Worked examples

1
Easy
Calculator
[2 marks]

A cone has radius 6 cm and height 10 cm.

Find its volume (3 significant figures).

Worked solution

\(V = \tfrac13 \pi r^2 h = \tfrac13 \pi(36)(10)\) M1
\(= 120\pi \approx 377\) cm³. A1

M1 \(\tfrac13\pi r^2 h\) A1 Correct answer of \(\approx377\)
2
Hard
Calculator
[4 marks]

A square-based pyramid has base side 10 cm and apex 12 cm directly above the centre.

Find the angle between a triangular face and the base (3 significant figures).

Worked solution

Distance from centre to base-edge midpoint \(= 5.\) M1
\(\tan\theta = \dfrac{12}{5}\) M1 A1
\(\theta = 67.4^{\circ}.\) A1

M1 Half base side M1 \(\tan\theta=h/5\) A1 Correct Substitution A1 \(\approx67.4^\circ\)
3
Hard
Calculator
[4 marks]

A bucket is a frustum with top radius 12 cm, base radius 8 cm, height 20 cm.

Find its volume (3 significant figures).

Worked solution

\(V = \tfrac13 \pi h (R^2 + Rr + r^2)\) M1
\(= \tfrac13 \pi(20)(144 + 96 + 64)\) A1
\(= \tfrac{20\pi}{3}(304)\) A1
\(\approx 6367\) cm³. A1

M1 Frustum formula A1 Correct substitution \(R^2+Rr+r^2\) A1 Working \(\tfrac{20\pi}{3}(304)\) A1 Correct answer of \(\approx6367\)

Common mistakes

Ready to practise properly?

11 3D geometry questions, marked instantly like the real exam.

Quick answers

How do you find the distance between two points in 3D?

\(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\) - the usual 2D distance formula with a third coordinate added.

How do you find the angle between a line and a plane?

Identify the right-angled triangle formed by the line, its projection onto the plane, and the perpendicular height between them, then use basic trig (usually \(\tan\)) to find the angle.

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