Binomial Distribution (AI HL)

A binomial random variable counts the number of successes across a fixed number of independent trials, each with the same success probability. This page covers the mean and variance formulas, how to spot when the model applies, and the GDC routines you'll use to find binomial probabilities - with worked examples and the mistakes that lose the most marks. It's part of the broader Probability & Distributions topic.

16 questions on this sub-topic.

Practise the binomial distribution → Try exam-style questions

Mean and variance

Covered under IB syllabus reference SL4.8: the binomial distribution, its mean and variance, and the situations where it's an appropriate model, found using technology. Neither formula is in the formula booklet, so both are worth memorising.

Mean

\(X\sim B(n,p)\): \(E(X)=np\)

Not in the formula booklet. The average number of successes over \(n\) trials.

Variance

\(\text{Var}(X)=np(1-p)\)

Not in the formula booklet. Note the \((1-p)\) factor - it's easy to drop under time pressure.

Need the full syllabus wording and formula-booklet reference table? See Probability & Distributions. For calculator routines, see the parent topic's GDC guidance.

Worked examples

1
Easy
GDC
[4 marks]

\(X \sim B(40, 0.3)\).

(a) Find \(E(X)\).
(b) Find \(\text{Var}(X)\).

Worked solution

(a) \(E(X) = np = 40(0.3)\) M1
\(= 12.\) A1

(b) \(\text{Var}(X) = np(1-p) = 40(0.3)(0.7)\) M1
\(= 8.4.\) A1

One‑variable statistics on the GDC - TI‑84 STAT▸CALC▸1‑Var Stats · Casio 1VAR · Nspire One‑Variable Statistics (enter data, and frequencies if grouped).

M1 \(np\) A1 Correct answer of \(12\) M1 \(np(1-p)\) A1 Correct answer of \(8.4\)
2
Medium
GDC
[4 marks]

In a factory, 4% of items are defective. A sample of 50 is taken. Let \(X\) be the number defective, modelled as binomial.

(a) Find \(P(X = 0).\)
(b) Find \(P(X \le 3).\)

Worked solution

(a) \(P(X=0) = (0.96)^{50}\) M1
\(\approx 0.130.\) A1

(b) \(P(X \le 3) \approx 0.861.\) M1 A1

M1 \(P(X=0)\) A1 Correct answer of \(\approx0.130\) M1 Binomcdf A1 Correct answer of \(\approx0.861\)
3
Hard
Calculator
[5 marks]

A seed germinates with probability 0.8. A gardener wants the probability of at least one germinating to exceed 0.999.

(a) Write an inequality for the number of seeds \(n\).

(b) Find the least \(n\).

Worked solution

(a) \(P(\ge 1) = 1 - (0.2)^n > 0.999 \Rightarrow (0.2)^n < 0.001.\) M1 A1 - \((0.2)^n<0.001\)

(b) \(n > \dfrac{\ln 0.001}{\ln 0.2} \approx 4.29\), so \(n\) M1
\(= 5.\) A1 A1

M1 Complement inequality A1 \((0.2)^n<0.001\) M1 Take logs A1 Correct answer of \(\approx4.29\) A1 \(n=5\)

Common mistakes

Ready to practise properly?

17 binomial-distribution questions, marked instantly like the real exam.

Quick answers

What is the mean of a binomial distribution?

If \(X \sim B(n,p)\), the mean is \(E(X) = np\).

What is the variance of a binomial distribution?

If \(X \sim B(n,p)\), the variance is \(\text{Var}(X) = np(1-p)\).

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