Poisson Distribution (AI HL)

The Poisson distribution models the number of times a rare, random event happens in a fixed interval of time or space - car crashes at a junction in an hour, typos on a page, flaws in a metre of cable. Unlike the binomial distribution it doesn't need a fixed number of trials, just a known average rate. This page covers the formula, the conditions that make it an appropriate model, and the mistakes that lose marks. It's part of the broader Probability & Distributions topic.

12 questions on this sub-topic.

Practise the Poisson distribution → Try exam-style questions

The formula and its conditions

Covered under IB syllabus reference AHL4.17. The probability formula and the mean/variance result are both in the formula booklet, but you're expected to justify when the model applies.

Poisson probability

\(X \sim \text{Po}(\lambda) \Rightarrow P(X=x) = \dfrac{e^{-\lambda}\lambda^{x}}{x!}\)

\(\lambda\) is the mean number of occurrences in the interval you're working over - rescale it first if the question's interval differs from the one \(\lambda\) was quoted for.

Mean and variance

\(E(X) = \text{Var}(X) = \lambda\)

The defining feature of a Poisson variable: its mean and variance are always equal. This is also the usual check for whether a Poisson model is appropriate for a real dataset.

Need the full syllabus wording and formula-booklet reference table? See Probability & Distributions. GDC keystrokes for these problems are in the same page's GDC section.

Worked examples

1
Medium
Calculator
[5 marks]

Emails arrive at a help desk at a mean rate of 2.5 per hour, following a Poisson distribution.

(a) Find the probability of exactly 6 emails in a 2-hour period.

(b) Find the probability of at least 1 email in a 30-minute period.

Worked solution

(a) In 2 hours \(\lambda = 5\): \(P(X=6) = \dfrac{e^{-5}5^6}{6!}\) M1
\(\approx 0.146.\) A1

(b) In 30 min \(\lambda = 1.25\): \(P(X \ge 1)\) M1
\(= 1 - e^{-1.25}\) A1
\(\approx 0.713.\) A1

M1 \(\lambda=5\) A1 Correct answer of \(\approx0.146\) M1 \(\lambda=1.25\) A1 \(1-e^{-1.25}\) A1 Correct answer of \(\approx0.713\)
2
Hard
Calculator
[2 marks]

Calls arrive at \(\lambda = 3\) per hour (Poisson).

Find \(P(X=2)\) in one hour, to 3 significant figures.

Worked solution

\(P(X=r) = \dfrac{e^{-\lambda}\lambda^r}{r!}.\) M1
\(\lambda=3, r=2\): \(P(X=2) = \dfrac{9e^{-3}}{2}\approx 0.224.\) A1

M1 Stating the correct Formula A1 Correct answer of \(\approx0.224\)

Common mistakes

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Quick answers

What is the formula for the Poisson distribution?

If \(X \sim \text{Po}(\lambda)\), then \(P(X=x) = \dfrac{e^{-\lambda}\lambda^x}{x!}\), where \(\lambda\) is the mean number of occurrences in the interval.

How do I know when a Poisson distribution is an appropriate model?

Events must occur independently of each other and at a uniform average rate over the interval in question. A sample mean close to the sample variance also supports a Poisson model.

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