Correlation (AI SL)

Pearson's product-moment correlation coefficient \(r\) tells you how strong a linear relationship is between two variables, and in which direction it points. This page covers reading and interpreting \(r\) - the sign, the magnitude, and the trap of assuming a strong correlation proves cause and effect. It's part of the broader Correlation & Regression topic.

33 questions on this sub-topic.

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Reading the coefficient

Covered under IB syllabus reference SL4.4: linear correlation of bivariate data, Pearson's product-moment correlation coefficient \(r\) calculated using technology, and the awareness that correlation does not imply causation.

Positive correlation

As \(x\) increases, \(y\) tends to increase too - points trend upward left to right, giving a positive gradient and \(r>0\).

Negative correlation

As \(x\) increases, \(y\) tends to decrease - points trend downward left to right, giving a negative gradient and \(r<0\).

No correlation

The points show no clear upward or downward trend - \(r\) is close to zero, and fitting a line wouldn't be meaningful.

Range of Pearson's correlation coefficient: \(-1\le r\le 1\) (not in the booklet - it's GDC output). Need the full syllabus wording and formula-booklet reference table? See Correlation & Regression. For calculator steps, see the parent topic's GDC guidance.

Worked examples

1
Easy
GDC
[4 marks]

For each value of \(r,\) state the strength and direction of the correlation.

(a) \(r=0.05\)
(b) \(r=-0.97\)
(c) \(r=0.62\)

Worked solution

Judge strength by \(|r|\) (near 1 = strong, near 0 = none) and direction by the sign. R1
\(\bullet\ r=0.05:\) \(|r|\) near 0 - very weak / essentially no linear correlation. A1
\(\bullet\ r=-0.97:\) \(|r|\) near 1 and negative - strong negative linear correlation. A1
\(\bullet\ r=0.62:\) mid-range and positive - moderate positive linear correlation. A1

Regression on the GDC - TI‑84 STAT▸CALC▸LinReg/ExpReg/PwrReg · Casio STAT▸CALC · Nspire Stat Calculations; turn DiagnosticOn for \(r\).

R1 Strength/sign rule A1 \(r=0.05\) A1 \(r=-0.97\) A1 \(r=0.62\)
2
Hard
GDC
[4 marks]

A strong positive data set has \(r=0.95.\) A single faulty reading far from the trend is added.

(a) State the likely effect on \(r.\)
(b) State what should be done before refitting.

Worked solution

(a) Effect on \(r.\) A point lying far from the existing trend disrupts the tight linear pattern, R1
so \(r\) is likely to decrease (move toward 0) - the correlation weakens. A1

(b) Before refitting. Investigate the suspect reading. R1
If it is a genuine error (mis-recorded or faulty measurement) it should be corrected or removed; only then refit the regression line. A1

R1 Disrupts pattern A1 \(r\) decreases R1 Investigate A1 Correct/remove then refit

Common mistakes

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Quick answers

What does Pearson's correlation coefficient r measure?

\(r\) measures the strength and direction of a linear relationship between two variables. It ranges from \(-1\) (perfect negative) to \(+1\) (perfect positive), with values near \(0\) showing little or no linear relationship. It is calculated using technology, not by hand.

Does a strong correlation mean one variable causes the other?

No. A strong \(r\) shows association, not cause and effect. A confounding factor could explain the relationship instead, so correlation alone never proves causation.

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