Logs & Exponents (AA SL)

Exponents describe repeated multiplication; a logarithm is the inverse operation, answering the question "what power do I need?" This topic covers the laws for combining exponents and logarithms, converting between the two forms, changing a logarithm's base so it can be evaluated on a calculator, and solving equations where the unknown sits in the exponent - a skill that comes up constantly in growth and decay modelling.

What the syllabus says

This topic maps onto two points in the official IB Analysis & Approaches syllabus.

CodeSyllabus content
SL1.5Laws of exponents with integer exponents. Introduction to logarithms with base 10 and \(e\). Awareness that \(a^x=b\) is equivalent to \(\log_a b = x\), where \(a>0\), \(b>0\). \(\log_e x = \ln x\).
SL1.7Laws of exponents with rational exponents. Laws of logarithms: \(\log_a(xy)=\log_a x+\log_a y\), \(\log_a(\tfrac{x}{y})=\log_a x-\log_a y\), \(\log_a(x^m)=m\log_a x\). Change of base of a logarithm. Solving exponential equations, including using logarithms.

These are core AA syllabus points, examined on both papers.

Key terms

Five words worth knowing cold before you touch the formulas below - each with a worked example showing exactly what it means.

What is an exponent?

An exponent, or index, tells you how many times a number (the base) is multiplied by itself. In \(2^5\), the base is 2 and the exponent is 5. Exponents can be positive, negative, or fractional, and each type follows its own rule for evaluating or simplifying the expression.

e.g. \(2^5 = 2\times2\times2\times2\times2 = 32\).

What is a logarithm?

A logarithm is the inverse of an exponent - it answers "what power do I need?" \(\log_a b = x\) means exactly the same thing as \(a^x = b\). Logarithms let you solve for an unknown exponent, which is otherwise hard to isolate algebraically.

e.g. \(\log_2 8 = 3\), since \(2^3 = 8\).

What are the laws of exponents?

The laws of exponents are rules for combining powers of the same base: multiplying adds the exponents, dividing subtracts them, and raising a power to a power multiplies them. They apply equally to integer, negative, and fractional exponents.

e.g. \(3^2 \times 3^4 = 3^{2+4} = 3^6 = 729\).

What are the laws of logarithms?

The laws of logarithms mirror the laws of exponents: the log of a product is a sum of logs, the log of a quotient is a difference of logs, and the log of a power brings the exponent out the front as a multiplier.

e.g. \(\log_2(8\times4) = \log_2 8 + \log_2 4 = 3+2 = 5\).

What is change of base?

Change of base lets you rewrite a logarithm in any base as a ratio of logarithms in a base your calculator supports, usually base 10 or \(e\). It's essential for evaluating logs like \(\log_5 12\), which most calculators can't compute directly.

e.g. \(\log_5 12 = \dfrac{\ln 12}{\ln 5} \approx 1.544\).

Key formulas

Six formulas cover almost every question on this topic. The two tables below summarise all of them at a glance - the explanations underneath go into more depth on each one.

Formula reference

The four logarithm laws are on the official formula booklet; the exponent rules are assumed prior knowledge and aren't listed separately.

FormulaUsed forBooklet?
\(\log_a(xy) = \log_a x + \log_a y\)Product law✓ Yes
\(\log_a\!\left(\tfrac{x}{y}\right) = \log_a x - \log_a y\)Quotient law✓ Yes
\(\log_a(x^m) = m\log_a x\)Power law✓ Yes
\(\log_a x = \dfrac{\log_c x}{\log_c a}\)Change of base✓ Yes
\(a^m \cdot a^n = a^{m+n}\)Exponent product ruleNot in booklet
\((a^m)^n = a^{mn}\)Exponent power ruleNot in booklet

Exponents vs logarithms

Every exponent law has a matching logarithm law, because a logarithm is just an exponent written the other way round. This table lines the two up side by side.

FeatureExponent formLogarithm form
Relationship\(a^x = b\)\(\log_a b = x\)
Combining (product)\(a^m \cdot a^n = a^{m+n}\)\(\log_a(xy) = \log_a x + \log_a y\)
Combining (quotient)\(a^m \div a^n = a^{m-n}\)\(\log_a\!\left(\tfrac{x}{y}\right) = \log_a x - \log_a y\)
Powers\((a^m)^n = a^{mn}\)\(\log_a(x^m) = m\log_a x\)
Example\(2^3 = 8\)\(\log_2 8 = 3\)

Laws of exponents

These rules only combine powers that share the same base - you can't simplify \(2^3 \times 3^4\) this way, since the bases differ.

Product rule

\[a^m \cdot a^n = a^{m+n}\]

Add the exponents when multiplying powers of the same base.

Not in the formula booklet - prior knowledge

Quotient rule

\[a^m \div a^n = a^{m-n}\]

Subtract the exponents when dividing powers of the same base.

Not in the formula booklet - prior knowledge

Power of a power

\[(a^m)^n = a^{mn}\]

Multiply the exponents when raising a power to another power.

Not in the formula booklet - prior knowledge

Laws of logarithms

The laws of logarithms only work when every logarithm in the expression shares the same base \(a\).

Product law

\[\log_a(xy) = \log_a x + \log_a y\]

The log of a product is the sum of the logs.

✓ In the formula booklet

Quotient law

\[\log_a\!\left(\tfrac{x}{y}\right) = \log_a x - \log_a y\]

The log of a quotient is the difference of the logs.

✓ In the formula booklet

Power law

\[\log_a(x^m) = m\log_a x\]

An exponent inside a log can be brought out the front.

✓ In the formula booklet

Worked examples

Two full exam-style questions, marked exactly like the real thing. Try each one yourself before checking the worked solution.

1
Easy
No calc
[3 marks]

Evaluate.

(a) \(\log_2 8\)

(b) \(\log_{10} 1000\)

(c) \(\ln e^3\)

Worked solution

(a) \(2^3=8\Rightarrow\log_2 8=3.\) A1

(b) \(10^3=1000\Rightarrow\log_{10}1000=3.\) A1

(c) \(\ln e^3=3\) (since \(\ln e=1\)). A1

A1 (a) A1 (b) A1 (c)
2
Medium
No calc
[5 marks]

\(2\log x+\log 3-\log y.\)

(a) Write it as a single logarithm.

(b) Solve \(\log_2 x+\log_2(x-2)=3\).

Worked solution

(a) \(\log\dfrac{3x^2}{y}.\) M1 A1

(b) \(\log_2[x(x-2)]=3\Rightarrow x^2-2x=8\Rightarrow x^2-2x-8=0.\) M1
\((x-4)(x+2)=0,\ x=4\) (reject \(x\) A1
\(=-2\)). A1

M1 Applying the log laws to combine the terms A1 Correct single logarithm M1 Combining the logs and forming the quadratic equation A1 Correct factorisation and both roots A1 Correct rejection of the invalid root, final value \(x=4\)

Common mistakes

The four slip-ups that account for most of the marks lost on this topic - worth reading before you start practising, not just after you get one wrong.

  • Splitting \(\log(x+y)\) into \(\log x + \log y\). Logarithms don't distribute over addition or subtraction - the product/quotient laws only apply to multiplication and division inside the log.
  • Confusing \((a^m)^n\) with \(a^{(m^n)}\). A power of a power multiplies the exponents - \((2^3)^2 = 2^6 = 64\) - which is not the same as a tower of exponents.
  • Sign errors with negative indices. \(a^{-n} = \dfrac{1}{a^n}\), not \(-a^n\) - a negative exponent means "reciprocal", not "negative value".
  • Forgetting to reject invalid roots. After solving a log equation, always check each solution makes every logarithm's argument positive - a root like \(x=-2\) in \(\log_2(x-2)\) must be discarded.

Using your GDC

Every step below is a real button sequence, not a vague "use your calculator" hint - covering the TI-84 Plus, TI-Nspire, and Casio fx-9860/fx-CG50. Pick your model to filter down to just the steps that apply to you.

Show steps for:
Enter scientific notation (standard form)

For very large or very small numbers - avoids typing long strings of zeros and prevents rounding errors, which matters when an exponential model gives a huge result.

  1. Scientific notation means \(a\times10^n\), e.g. \(3.2\times10^8\) or \(4.5\times10^{-3}\).
  2. Use 2nd → , (EE) to enter the ×10 part: type 3.2 2nd , 8 to enter 3.2×10⁸. Do NOT type ×10^ separately.TI-84
  3. Use the EE key (or type ×10^ from the keyboard template) to enter scientific notation. Or just type 3.2×10^8 using the ^ key.Nspire
  4. Use the ×10ᴉ key (EXP key) - type 3.2 then EXP then 8. Do NOT type ×10^ manually.Casio
  5. To display answers in scientific notation: on TI-84 press MODE and choose SCI; on Casio set the display mode in SET UP.

Tip: A common mistake is typing ×10^ instead of using the EE/EXP key - this gives ×10×... (multiplication, then a power) rather than proper scientific notation.

Solve an equation numerically (including multiple solutions)

Faster and safer than algebra for messy exponential equations - and it finds every solution, not just one.

  1. Graph \(f(x)\) first so you can see how many solutions exist and roughly where they are.
  2. Rearrange so everything is on one side: \(f(x) = 0\) - or graph both sides as separate functions and find intersections.
  3. MATH → Solver: enter the expression, type a starting guess close to one root, press ALPHA + ENTER. Move the guess to near a different root and repeat for each solution.TI-84
  4. Type nSolve(f(x)=0, x, guess) - include a guess or interval e.g. nSolve(f(x)=0, x, 2) or nSolve(f(x)=0, x, {1,5}) to target a specific root.Nspire
  5. Run-Matrix → SolveN(f(x), x) returns all real roots at once; or use the Equation app for a visual approach.Casio
  6. For transcendental equations (e.g. \(e^x = 3x\)), graph both sides, count crossings, then use the intersection tool for each one.
  7. Always verify each solution by substituting back into the original equation.

Tip: The solver finds ONE root near your starting guess - change the guess to find others. The graph shows you how many to expect.

See the full GDC guide for more calculator models and topics.

Ready to practise properly?

Logs & exponents questions, marked instantly like the real exam.

Quick answers

The questions students on this topic ask most often.

What's the difference between an exponent and a logarithm?

An exponent tells you how many times to multiply a base by itself (\(2^3 = 8\)). A logarithm is the inverse - it tells you what exponent you'd need (\(\log_2 8 = 3\)). They describe the same relationship from opposite directions.

When do I need the change of base formula?

Whenever you need to evaluate a logarithm in a base your calculator doesn't have a dedicated button for. \(\log_a x = \dfrac{\log_c x}{\log_c a}\) lets you switch to base 10 or base \(e\), which every calculator supports.

How do I solve an exponential equation like \(3^x = 20\)?

Take logarithms of both sides. \(3^x = 20\) becomes \(x\ln 3 = \ln 20\), so \(x = \dfrac{\ln 20}{\ln 3}\). This works for any base, and any calculator can evaluate the natural logs at the end.

Can I use my GDC for this topic?

Yes, on Paper 2 - your calculator can evaluate a logarithm in any base and solve exponential equations numerically. On Paper 1 you'll need the laws above without a calculator. See the GDC guide for model-specific instructions.

Sub-topics

Logs & Exponents broken down into its individual skills, each with its own focused page.

Related topics

More Number & Algebra topics from the same AA SL syllabus unit, in case you want to keep going.