Function Notation and Types (AA SL)

Before you can transform or sketch a graph, you need to be fluent in reading one: what \(f(x)\) means, and how to pull intercepts, turning points and asymptotes straight off an equation without a diagram to guide you. This page drills that skill across the function types AA SL uses most - quadratics, cubics and rationals - as a foundation for the broader Graphs & Transformations topic.

13 questions on this sub-topic.

Practise function notation → Try exam-style questions

Reading a function

Covered under IB syllabus references SL2.2 and SL2.4. Neither of these is a formula-booklet entry - they're definitions and a checklist of features you're expected to extract from an equation on sight.

Function notation

\(f(x)\)

\(f(x)\) is the output of \(f\) for input \(x\). \(f(0)\) gives the \(y\)-intercept; solving \(f(x)=0\) gives the \(x\)-intercept(s). The domain is every valid input; the range is every value the output can take.

Key features to find

Intercepts, turning points, asymptotes

\(x\)-intercepts (\(f(x)=0\)), \(y\)-intercept (\(f(0)\)), turning points (from a completed square or \(f'(x)=0\)), and any vertical or horizontal asymptotes.

Need graph transformations or the syllabus wording for this section? See Graphs & Transformations.

Worked examples

1
Easy
No calc
[5 marks]

Let \(f(x)=x^2-5x+6\).

(a)(i) Find the \(x\)-intercept with \(x<2.5\).
(a)(ii) Find the \(x\)-intercept with \(x>2.5\).
(b) Find the \(y\)-intercept.
(c) Write down the equation of the axis of symmetry.

Worked solution

(a) \(x^2-5x+6=0\Rightarrow(x-2)(x-3)=0\Rightarrow x=2\) or \(x=3.\) M1
\(x=2.\) A1
A1

(b) \(f(0)=6.\) The \(y\)-intercept is \((0,6).\) A1

(c) \(x=\dfrac{2+3}{2}=2.5.\) A1

M1 Factorisation A1 \(x=2\) A1 \(x=3\) A1 \(y\)-intercept A1 Axis of symmetry
2
Medium
Calculator
[4 marks]

Let \(f(x)=x^3-3x^2-x+3\).

(a)(i) Find the \(x\)-intercept with \(x<0\).
(a)(ii) Find the \(x\)-intercept with \(0<x<2\).
(a)(iii) Find the \(x\)-intercept with \(x>2\).
(b)(i) Write down the coordinates of the local maximum.
(b)(ii) Write down the coordinates of the local minimum.

Worked solution

(a) Using GDC (or factorisation): \(f(x)=(x-3)(x-1)(x+1)\), so \(x=-1,\,1,\,3.\) M1 A1

(b) Solving \(f'(x)=3x^2-6x-1=0\) gives \(x=\dfrac{6\pm\sqrt{48}}{6}=1\pm\dfrac{2\sqrt3}{3}\), i.e. \(x\approx-0.155\) or \(x\approx2.15\). Local maximum \(\approx(-0.155,\,3.08)\), local minimum \(\approx(2.15,\,-3.08).\) A1 A1

🧮 GDC: Graph the function and use the maximum/minimum finder.

M1 Method; \(x=-1\) A1 \(x\)-intercept \(x=1\) A1 Local max A1 Local min

Common mistakes

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14 function-notation questions, marked instantly like the real exam.

Quick answers

What does f(x) actually mean?

\(f(x)\) is the output (\(y\)-value) that the function \(f\) produces for the input \(x\). Writing \(f(3)=7\) means the point \((3,7)\) lies on the graph of \(y=f(x)\).

What is the difference between the x-intercept and the y-intercept?

The \(y\)-intercept is found by evaluating \(f(0)\). The \(x\)-intercept(s) are found by solving \(f(x)=0\). They use the same equation in opposite directions, so mixing them up is one of the most common exam errors.

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